Nucleic Acids
Guiding Questions:
- How does the structure of nucleic acids allow hereditary information to be stored?
- How does the structure of DNA facilitate accurate replication?

SL and HL Content
Learning Objective A1.2.1 - DNA as the Genetic Material of All Living Organisms
DNA – The Universal Genetic Code
Deoxyribonucleic acid (DNA) is the molecule that stores the long-term genetic information in all living organisms.
This information provides the instructions for building proteins, which determine how cells function.
Core idea: DNA → genes → proteins → cell structure & function

Because DNA can be accurately replicated, it allows genetic information to be:
passed from cell to cell during growth
passed from parent to offspring during reproduction
DNA as Evidence of Common Ancestry
All living organisms use DNA as their genetic material.
This universality suggests that all life shares a common evolutionary origin.
This supports the idea that:
life evolved from a common ancestor
the genetic code is fundamentally shared across all species
Gene Expression: Same DNA, Different Cells

In multicellular organisms:
all cells contain the same DNA
but only specific genes are expressed in each cell
This leads to:
cell specialization
different structures and functions despite identical genetic material
What About Viruses?

Some viruses use:
DNA as genetic material
others use RNA
Examples:
DNA viruses → bacteriophages
RNA viruses → HIV, coronaviruses
Why This Does NOT Contradict the DNA Rule
The learning objective states that all living organisms use DNA as their genetic material. However, viruses are not classified as living organisms.
A virus is simply:
a nucleic acid core (DNA or RNA)
surrounded by a protein coat
with no cellular machinery of its own
Because of this, viruses:
cannot reproduce independently
they must infect a host cell
do not carry out metabolism
do not respond to stimuli independently
So Why Doesn’t RNA in Viruses Falsify the DNA Claim?
Since viruses are not living, they are not exceptions to the rule.
therefore, the presence of RNA in some viruses does not contradict the idea that DNA is the genetic material of all living organisms.
In fact, the dependence of viruses on host cells highlights that only living cells with DNA have the full capacity for independent life.
🔍 IB EXAM FOCUS
⚠️ Always state: “viruses are not considered living”
Be ready to explain:
DNA as evidence for common ancestry
Why universality of DNA supports evolution
You MUST be able to link: DNA → genes → proteins → cell function
This is the foundation of gene expression and cell differentiation
Common exam traps:
Saying “all organisms use DNA” ❎
→ Must say all living organisms ✅
A1.2.2 - Components of a nucleotide
What is a Nucleotide?
A nucleotide is the basic building block (monomer) of nucleic acids (DNA and RNA).

Each nucleotide is made of three components:
Phosphate group - circle
Pentose sugar (5-carbon sugar) - pentagon
Nitrogenous base - rectangle
Key Structural Details

The pentose sugar has 5 carbon atoms:
Base attaches to Carbon #1 (C1)
Phosphate attaches to Carbon #5 (C5)
This positioning is what allows nucleotides to link together to form long chains (polymers)
🔍 IB EXAM FOCUS
You may be asked to:
draw a nucleotide from memory
identify components in a diagram
label phosphate, sugar, and base correctly
Common mistakes:
Not showing correct relative positioning
A1.2.3 - Sugar - Phosphate Bonding & Backbone
How Nucleotides Join Together
Nucleotides are linked by covalent bonds called phosphodiester bonds.
These form between:
phosphate of one nucleotide
sugar of the next nucleotide
Formation of the Backbone
Repeating linkage creates a:
👉 sugar–phosphate backbone
This backbone:
runs along the length of the DNA/RNA strand
is made of alternating:
sugar → phosphate → sugar → phosphate
Key Functional Importance
The backbone:
is strong and stable (covalent bonds)
protects the sequence of bases
gives structure to the molecule
The bases project inward, allowing base pairing and genetic coding
Reminder: Polymer Formation
Nucleic acids are polymers formed by condensation reactions
Each bond formation:
releases a molecule of water
🔍 IB EXAM FOCUS
IB LOVES asking:
What type of bond joins nucleotides → covalent bond, specifically a phosphodiester bond
What forms the backbone → alternating sugar-phosphate chain
Common mistake:
Saying “bonds between bases form the backbone”
→ backbone is ONLY sugar-phosphate
A1.2.4 – Nitrogenous Bases & the Genetic Code
The Nitrogenous Bases
DNA bases:
• Adenine (A)
• Thymine (T)
• Cytosine (C)
• Guanine (G)
RNA bases:
• Adenine (A)
• Uracil (U) (instead of thymine)
• Cytosine (C)
• Guanine (G)
Key Differences (DNA vs RNA)
• DNA uses thymine (T)
• RNA uses uracil (U)
This is the ONLY base difference
Bases Form the Genetic Code
• Each nucleotide contains one base
• The sequence of bases stores genetic information
• This sequence:
• forms genes
• determines amino acid sequences
• ultimately determines protein structure and function
Why Base Sequence Matters
• Different sequences → different proteins
• Different proteins → different:
• cell structures
• cell functions
This is the basis of biological diversity
IB EXAM FOCUS
• You MUST:
5/23
• know all base names (not just letters)
• distinguish DNA vs RNA bases
• IB often asks:
• role of base sequence → genetic information storage
• link: base sequence → gene → protein → phenotype
• Always phrase as:
• “The sequence of nitrogenous bases forms the genetic code”
• Then link to protein synthesis
6/23
A1.2.5 – Structure of RNA
RNA as a Polymer
• RNA (ribonucleic acid) is a single-stranded polymer made of nucleotide monomers
• Nucleotides are joined by condensation reactions
• Forms phosphodiester bonds
• Water is released each time a bond forms
If a chain has n nucleotides, it forms (n − 1) bonds & (n − 1) water molecules
For example a if an RNA chain has 4 nucleotides:
• it forms 3 phosphodiester bonds and 3 water molecules are released
Key Structural Features
• RNA consists of:
• Ribose sugar
• Phosphate backbone
• Nitrogenous bases (A, U, C, G)
Recognising RNA in Diagrams
• Look for:
• Single strand (NOT double)
• Presence of uracil (U) instead of thymine
IB EXAM FOCUS
• IB commonly tests:
• Condensation reactions → water released
• Identification of RNA vs DNA from diagrams
• Common mistakes:
• Forgetting uracil replaces thymine
Always phrase as:
“RNA is a single-stranded polymer formed by condensation of RNA nucleotide monomers
via phosphodiester bonds”
7/23
A1.2.6 – Structure of DNA
DNA as a Double Helix
• DNA (deoxyribonucleic acid) consists of two strands of nucleotides.
• Each strand has a sugar–phosphate backbone
• The nitrogenous bases face inward & form “rungs” of the ladder
• These strands:
• twist into a double helix
• are held together by hydrogen bonds between bases
Antiparallel Structure
• The two strands run in opposite directions:
• one strand: 5’ → 3’
• other strand: 3’ → 5’
Complementary Base Pairing
• Bases pair specifically:
• Adenine (A) Thymine (T) - with 2 hydrogen bonds
• Guanine (G) Cytosine (C) - with 3 hydrogen bonds
• This ensures accurate replication and a stable structure.
Diagram Expectations (VERY important)
You should be able to:
• draw two strands
• show antiparallel orientation
• show correct base pairing (A–T , G–C)
IB EXAM FOCUS
• IB LOVES asking:
• define antiparallel
• explain complementary base pairing
• identify errors in DNA diagrams
• Common mistakes:
• Both strands drawn in same direction 🆇
8/23
A1.2.7 – Differences Between DNA and RNA
Key Structural Differences
Feature DNA RNA
Strands Double-stranded Single-stranded
Sugar Deoxyribose Ribose
Bases A, T , C, G A, U, C, G
Sugar Structure Difference: Ribose vs. Deoxyribose
• Ribose (RNA):
• has –OH group on carbon 2
• Deoxyribose (DNA):
• has H instead of OH
• → one less oxygen
This is the ONLY structural sugar difference
Functional Differences
• DNA:
• long-term genetic storage
• stable structure
• RNA:
• involved in protein synthesis
• shorter-lived and more flexible
Examples of RNA (IMPORTANT)
• mRNA (messenger RNA) → carries genetic code from DNA
• tRNA (transfer RNA) → brings amino acids
• rRNA (ribosomal RNA) → forms ribosomes
IB EXAM FOCUS
• IB frequently asks:
• compare DNA vs RNA (table or structured answer)
• identify differences in strands, bases, sugar
• For “compare” questions, ALWAYS structure answers like:
• DNA is
___, whereas RNA is
___
9/23
• DNA contains
___, whereas RNA contains
___
Direct comparison = higher marks
10/23
A1.2.8 – Importance of Complementary Base Pairing
Reminder: DNA bases pair in a specific and predictable way:
• Adenine (A) Thymine (T)
• Cytosine (C) Guanine (G)
• This pairing occurs due to hydrogen bonding
• weak individually, but strong collectively
Why Complementarity Matters
1. Accurate DNA Replication
• During replication, DNA strands separate and each strand acts as a template
• Free nucleotides pair with complementary bases on the template strand
• This ensures:
• exact copying of genetic information
• production of identical DNA molecules
2. Gene Expression (Protein Synthesis)
• Complementary base pairing is also essential in:
• Transcription (DNA → RNA)
• Translation (RNA → protein)
• This ensures:
• correct amino acid sequence
• correct protein structure and function
Key Idea
Complementarity = information is preserved AND accurately used
IB EXAM FOCUS
• IB commonly asks:
• explain how complementary base pairing ensures accuracy
• link base pairing to replication AND transcription
A1.2.9 – DNA’s Capacity to Store Information
DNA Stores Information in Base Sequences
• Genetic information is stored in the sequence of nitrogenous bases
• Each sequence:
• represents a gene or regulatory region
11/23
Enormous Diversity of Sequences
• There are 4 possible bases:
• A, T , C, G
• For a sequence of length n : possible combinations = 4ⁿ
Examples:
• 1 base → 4 possibilities
• 3 bases → 64 possibilities
• 10 bases → over 1 million possibilities
Real DNA molecules:
• contain millions to billions of bases
“Limitless” Storage Capacity
• DNA can vary in length AND vary in sequence
• This creates virtually unlimited combinations
Efficiency of DNA Storage
• DNA stores massive information in a very small space
Example:
• DNA molecules are extremely thin (~2 nm wide), yet can encode entire organisms
• Therefore it has high information density
Key Idea
DNA = high-capacity, compact information storage system
IB EXAM FOCUS
• IB LOVES questions like:
• “Explain why DNA has a large capacity for storing information”
• Common mistakes:
• only saying “DNA is long”
• not explaining how combinations arise
• Full-mark phrase:
“The sequence of four bases can vary in any order and length, producing an exponential
number of possible combinations (4ⁿ), giving DNA a large capacity to store information.
”
12/23
A1.2.10 – Universal Genetic Code & Common Ancestry
The Genetic Code is Universal
• The genetic code is the way base sequences are translated into amino acids
• In ALL living organisms:
• the same codons code for the same amino acids
What This Means
All organisms use the same molecular “language”
• DNA → RNA → protein works the same way in bacteria, plants & animals
Evidence for Common Ancestry
• If all organisms share the same genetic code:
they must have inherited it from a common ancestor
• This suggests:
• life originated once
• and diversified through evolution
Small Variations
• There are minor exceptions
• some codons may differ slightly in rare organisms
• BUT overall the genetic code is highly conserved
Key Idea
Universal code = strong molecular evidence for evolution
IB EXAM FOCUS
• IB commonly asks:
• explain how the genetic code supports common ancestry
• Must include:
same codon → same amino acid
shared across all life
implies inheritance from a common ancestor
• Common mistakes:
• just saying “all organisms use DNA” (too vague)
• not linking to evolution/common ancestry
13/23
Additional HL
A1.2.11 – Directionality of RNA and DNA
What Does “Directionality” Mean?
• DNA and RNA strands have polarity (direction) due to how nucleotides are linked
• Each strand has:
• a 5′ (five-prime) end → phosphate group attached to C5
• a 3′ (three-prime) end → hydroxyl (–OH) group on C3
These ends are chemically different, giving the strand direction
3′
–5′ Linkage (Phosphodiester Bond)
• Nucleotides are joined by a phosphodiester bond between:
• 3′ carbon of one sugar
• 5′ phosphate of the next nucleotide
This creates a:
• sugar–phosphate backbone
• repeating 3′
–5′ linkage pattern
Key Consequence: Synthesis is ALWAYS 5′ → 3′
• New nucleotides are always added to the:
3′ end of the growing strand
• Therefore:
strands are synthesized in the 5′ → 3′ direction
Why Directionality Matters
1. DNA Replication
• DNA polymerase adds nucleotides only to the 3′ end
• Result:
replication proceeds 5′ → 3′
• Leads to:
• leading strand (continuous)
• lagging strand (discontinuous)
2. Transcription (DNA → RNA)
• RNA polymerase:
• also adds nucleotides to the 3′ end
RNA is synthesized:
14/23
• 5′ → 3′
3. Translation (RNA → Protein)
• Ribosome:
• reads mRNA in the 5′ → 3′ direction
Directionality ensures:
• correct reading of codons
• correct amino acid sequence
Big Picture Link
• Directionality = enzymes only work in one orientation
• ensures accuracy and consistency across all processes
IB EXAM FOCUS
• IB LOVES:
• “Explain why DNA/RNA synthesis occurs in a 5′ → 3′ direction”
• Must include:
nucleotides added to 3′ end
phosphodiester bond (3′
–5′ linkage)
applies to replication AND transcription
15/23
A1.2.12 – Purine–Pyrimidine Pairing & DNA Stability
Two Types of Nitrogenous Bases
Purines (double-ring structure)
• Adenine (A)
• Guanine (G)
Pyrimidines (single-ring structure)
• Cytosine (C)
• Thymine (T)
One purine ALWAYS pairs with one pyrimidine
Why This Matters for Structure
Constant Width of DNA
• Purines = large (2 rings)
• Pyrimidines = small (1 ring)
Pairing:
• purine + pyrimidine = constant width
What If Pairing Was Different?
• Purine + purine → too wide
• Pyrimidine + pyrimidine → too narrow
• this would distort the DNA structure
Result: Stable Double Helix
• Uniform base pairing ensures consistent spacing between strands & stable double helix
shape
Key Idea
• DNA stability depends on:
• complementary base pairing
• purine–pyrimidine matching
IB EXAM FOCUS
• IB commonly asks:
• “Explain why purine–pyrimidine pairing is important”
• Must include:
16/23
difference in size (double vs single ring)
ensures constant distance between strands
maintains stable double helix structure
17/23
A1.2.13 – Structure of a Nucleosome
Why DNA Needs Packaging
• DNA is an extremely long molecule (~2 metres in a single human cell)
• It must:
• fit inside the nucleus (~µm scale)
• remain organized and accessible
Solution: DNA is packaged efficiently using proteins called histones
What is a Nucleosome?
• A nucleosome is the basic unit of DNA packaging
• Structure:
• DNA wrapped around a core of histone proteins
Core Structure
• The nucleosome core contains:
• 8 histone proteins (histone octamer)
• DNA:
• wraps around this core ~2 times
Linker DNA & Additional Histone
• Between nucleosomes:
• linker DNA connects them
• An additional histone protein (H1):
• helps hold DNA in place
• stabilizes the nucleosome structure
“Beads on a String” Model
• Nucleosomes appear like beads on a string
Where:
• beads = nucleosomes
• string = DNA
Higher-Level Packaging
• Nucleosomes:
• coil further → form chromatin
• condense → form chromosomes
18/23
• This allows DNA to be:
• tightly packed
• still accessible when needed
Key Functional Ideas
• Histones are positively charged
• DNA is negatively charged
• This allows strong attraction → DNA wraps tightly around histones
Prokaryote vs Eukaryote Link
• Eukaryotes:
• DNA packaged with histones → nucleosomes
• Prokaryotes:
• no histones
• DNA is “naked”
Key Idea
Nucleosomes allow DNA to be:
• compact
• organized
• functionally accessible
IB EXAM FOCUS
• IB typically asks:
• “Describe the structure of a nucleosome”
• Must include:
DNA wrapped around 8 histone proteins
presence of linker DNA
role of additional histone (H1)
19/23
A1.2.14 – Evidence from the Hershey–Chase Experiment
The Big Question
Before the 1950s, scientists were unsure:
What is the genetic material?
• DNA
• or proteins
Why proteins seemed likely:
• proteins have 20 amino acids → more complex
• DNA has only 4 bases → seemed too simple
The Key Idea of the Experiment
Hershey and Chase used:
• bacteriophages (viruses that infect bacteria)
Structure of a virus:
• protein coat
• DNA inside
When a virus infects a cell:
• it injects its genetic material into the bacterium
Experimental Design
• They used radioactive labeling to track what enters the cell:
Two separate experiments:
Protein-labelled virus
• labelled with ³⁵S (sulfur)
• sulfur is found in proteins, NOT DNA
DNA-labelled virus
• labelled with ³²P (phosphorus)
• phosphorus is found in DNA, NOT proteins
Key Procedure Steps
• Viruses infect bacteria
• Mixture is blended → removes viral coats
20/23
• Centrifuged:
• pellet = bacteria
• supernatant = viral coats
Then measure radioactivity
Results
• ³²P (DNA):
found in the pellet (inside bacteria)
• ³⁵S (protein):
found in the supernatant (outside cells)
Conclusion
• DNA enters the cell and controls replication
• Protein does NOT enter the cell
• Therefore: DNA is the genetic material
Why This Works (Critical Logic)
• Only the material that enters the cell and directs production of new viruses
• can be the genetic material
That material = DNA
Nature of Science (NOS)
• This experiment was only possible because of:
radioisotopes (³²P and ³⁵S)
• Shows:
• advances in technology → enable new discoveries
• science builds on tools + methods
IB EXAM FOCUS
• IB will NOT ask you to just “describe the experiment”
• They ask:
• “Explain how the results support DNA as genetic material”
What You MUST Include
• DNA labelled with ³²P → found inside cells (pellet)
• Protein labelled with ³⁵S → remains outside (supernatant)
• Only DNA enters the cell
• Therefore DNA controls viral replication
21/23
Common Mistakes
• just describing steps without linking to conclusion
• forgetting which isotope labels what
• not mentioning pellet vs supernatant
• saying “DNA is important” instead of explicit conclusion
A1.2.15 – Chargaff’s Rule
Chargaff’s Key Findings
• Erwin Chargaff analysed DNA from many different organisms and measured the
proportions of the four bases:
• Adenine (A)
• Thymine (T)
• Guanine (G)
• Cytosine (C)
He discovered two consistent patterns:
• The amount of adenine ≈ thymine
• The amount of guanine ≈ cytosine
This became known as Chargaff’s Rule
Important Insight
Although: A = T & G = C
The overall proportions vary between species
This shows:
DNA is NOT identical across organisms → genetic diversity exists
Why This Was a Big Deal
Before Chargaff:
• Scientists believed the tetranucleotide hypothesis
• DNA = repeating pattern: A-T-G-C-A-T-G-C-A-T-G-C...
This would mean:
• DNA is too simple
• Cannot store complex genetic information
Chargaff’s data showed:
• Base proportions are NOT equal overall
22/23
• DNA is NOT repetitive
Therefore:
• DNA sequence is variable
Link to DNA Structure
Chargaff’s findings helped explain: complementary base pairing
This directly supported:
• the double helix model
• base pairing rules used in replication & transcription
Nature of Science (NOS)
Problem of Induction vs Falsification
• Induction: forming general conclusions from observations
→ always uncertain
• Falsification: proving an idea is wrong
→ much stronger scientifically
In this case:
• Scientists assumed DNA had a repeating structure
• Chargaff’s data contradicted this
Therefore:
The tetranucleotide hypothesis was falsified
IB EXAM FOCUS
What IB expects you to state:
• No. of A = T and G = C
• Base composition varies between species
• DNA is not repetitive
• This falsified the tetranucleotide hypothesis
High-Scoring Answer Structure
3–4 mark answer:
“Chargaff found that the proportion of adenine equals thymine and guanine equals
cytosine in DNA. However, the overall proportions of bases vary between species. This
showed that DNA is not composed of a repeating tetranucleotide sequence, thereby
falsifying the tetranucleotide hypothesis."
